(5-x)во 2 степени -x(2,5+x)​=0

Ответ:

[tex](5 - x) {}^{2} - x(2.5 + x) = 0 \\ 25 - 10x + x {}^{2} - 2.5x - x {}^{2} = 0 \\ 25 - 10x - 2.5x = 0 \\ - 10x - 2.5x = - 25 \\ - 12.5x = - 25 \\ x = - 25 \div - 12.5 \\ x = 2[/tex]