решите неравенство (х-8)^<√3(х-8)

[tex](x-8)^2\ \textless \ \sqrt3(x-8)\\\\x-8=t,\; \; t^2-\sqrt3t\ \textless \ 0\\\\t(t-\sqrt3)\ \textless \ 0\\\\+++(0)---(\sqrt3)+++\\\\0\ \textless \ t\ \textless \ \sqrt3\\\\0\ \textless \ x-8\ \textless \ \sqrt3\\\\8\ \textless \ x\ \textless \ 8\sqrt3[/tex]