решите пожалуйста
1)5x(x-2)-2x+4-4x(x-2)=0
2)9x-3-2(3x-1)+5x(3x-1)=0

[tex]5x(x-2)-2x+4-4x(x-2)=0 4 - 2x + x(x - 2) = 0 x^2 - 4x + 4 = 0 (x - 2)^2 = 0 x - 2 = 0 x1,2 = 2[/tex]

[tex]9x - 3 - 2(3x - 1) + 5x(3x - 1) = 0 15x^2 - 2x - 1 = 0 (3x - 1)(5x + 1) = 0 3x - 1 = 0 ; 5x + 1 = 0 [/tex]
[tex]x1 = \frac{1}{3} ; x2 = -0,2 [/tex]