1. (16\25)^x+3=(125\64)^2
решите пж

[tex] ( \frac{16}{25} )^{x+3}=( \frac{125}{64})^2\\\\(( \frac{4}{5})^2)^{x+3}=(( \frac{5}{4})^3)^2\\\\ ( \frac{4}{5})^{2x+6}=( \frac{4}{5})^{-6}\\\\2x+6=-6\\2x=-12\\x=-6 [/tex]