x^2 + 2y = 12
2x - y = 10

[tex] \left \{ {{x^2+2y=12} \atop {2x-y=10}} \right. \\y=2x-10 \\x^2+2(2x-10)=12 \\x^2+4x-20-12=0 \\x^2+4x-32=0 \\D=16+128=144=12^2 \\x_1= \frac{-4+12}{2} =4 \\x_2= \frac{-16}{2} =-8 \\y_1=2*4-10=8-10=-2 \\y_2=-8*2-10=-16-10=-26[/tex]
Ответ: (4;-2), (-8;-26)