решите пример 2 1\6+2 1\12 *(0.82:0.4-2.75*1.2) 

[tex]2\dfrac{1}{6}+2\dfrac{1}{12}\cdot(0,82\div0,4-2,75\cdot1,2)=\dfrac{13}{6}+\dfrac{25}{12}\cdot(2,05-3,3)=\\\\\\ =\dfrac{13}{6}+\dfrac{25}{12}\cdot(-1,25)=\dfrac{13}{6}+\dfrac{25}{12}\cdot\bigg(-\dfrac{5}{4}\bigg)=\dfrac{13}{6}-\dfrac{125}{48}=\\\\\\ =\dfrac{104}{48}-\dfrac{125}{48}=-\dfrac{21}{48}=-\dfrac{7}{16}=\bold{-0,4375}[/tex]