найдите корень выражения 7 1/5-(6 1/5-х)=2 1/5

[tex]7\frac{1}{5}-(6\frac{1}{5}-x)=2\frac{1}{5}[/tex]
[tex]7\frac{1}{5}-6\frac{1}{5}+x=2\frac{1}{5}[/tex]
[tex]x=2\frac{1}{5}+6\frac{1}{5}-7\frac{1}{5}[/tex]
[tex]x=1\frac{1}{5}[/tex]