Z•(10+4i)=7-9i решитттеее плиз

[tex]z= \frac{7-9i}{10+4i} = \frac{(7-9i)(10-4i)}{(10+4i)(10-4i)} = \frac{70-28i-90i+36i^2}{10^2-(4i)^2} = \\ \\ = \frac{70-118i-36}{100+16} = \frac{34-118i}{116} = \frac{2*(17-59i)}{2*58} = \frac{17-59i}{58} = \\ \\ = \frac{17}{58}- \frac{59i}{58} .[/tex]