(15а²-10ab)/(3ab-2b²)   a= -2  b= -0.1

[tex] \frac{(15 a^{2} - 10ab)}{(3ab-2b^{2})} [/tex]= [tex] \frac{5a(3a-2b)}{b(3a-2b)} [/tex]= [tex] \frac{5a}{b} [/tex];
[tex] \frac{-10}{-0,1} [/tex]=100
Ответ: 100