Решите уравнения:
1) x+8 целых 1/11=16,1
2) y-9,7=8 целых 2/3

1.
[tex]x + 8 \frac{1}{11} = 16.1[/tex]
[tex]x + \frac{8}{11} = 16.1[/tex]
[tex]x = 16.1 - \frac{8}{11} [/tex]
[tex]x = \frac{161}{10 } - \frac{8}{11} [/tex]
[tex]x = \frac{1691}{110} [/tex]

2.
[tex]y - 9.7 = 8 \frac{2}{3} [/tex]
[tex]y - 9.7 = \frac{16}{3} [/tex]
[tex]y = \frac{16}{3} + 9.7[/tex]
[tex]y = \frac{16}{3} + \frac{97}{10} [/tex]
[tex]y = \frac{451}{30} [/tex]

1)х+8 1/11=16,1
х=16 1/10-8 1/11
х= 8 1/110

2)у-9,7=8 2/3
у=8 2/3+9 7/10
у=18 11/30