решите неравенство (x-4)/(x-3)≤0;

[tex] \frac{(x-4)} {(x-3)} \leq 0[/tex]

[tex] 1) \left \{ {{(x-4)} \leq 0 \atop {(x-3)\ \textgreater \ 0}} \right. [/tex]

[tex] \left \{ {{x} \leq 4 \atop {x\ \textgreater \ 3}} \right. \Rightarrow 3\ \textless \ x \leq 4[/tex]

2) [tex]\left \{ {{(x-4)} \geq 0 \atop {(x-3)\ \ \textless \ \ 0}} \right. [/tex]

[tex]\left \{ {{x} \ \geq \ 4 \atop {x\ \ \textless \ \ 3}} \right. \Rightarrow[/tex] нет решения

Ответ: [tex]3\ \textless \ x \leq 4[/tex]