Решить неравенство;
(1/2)^x+3>16

[tex]\left(\frac12\right)^{x+3}\ \textgreater \ 16\\2^{-(x+3)}\ \textgreater \ 2^4\\-(x+3)\ \textgreater \ 4\\-x-3\ \textgreater \ 4\\-x\ \textgreater \ 7\\x\ \textless \ -7[/tex]