Найдите корни уравнения: х+2/х=7 2/7

ОДЗ: х≠0

[tex]x+\frac{2}{x} =7\frac{2}{7}\\\\ \frac{x^{2}+2 }{x}=\frac{51}{7}\\\\7(x^{2} +2)=51x\\ \\ 7x^{2} -51x+14=0\\\\ D=51^2-4*14*7=2209=47^2\\\\x_1=\frac{51-47}{14}=\frac{2}{7}\\ \\ x_2=\frac{51+47}{14}=7[/tex]