Анонимно

Вычислить определитель: 1 -5 4 3 1 7 0 2 7 0 4 1 1 0 6 7

Ответ

Анонимно
[tex] \left[\begin{array}{cccc}1&-5&4&3\\1&7&0&2\\7&0&4&1\\1&0&6&7\end{array}\right] =1* \left[\begin{array}{ccc}7&0&2\\0&4&1\\0&6&7\end{array}\right] -1* \left[\begin{array}{ccc}-5&4&3\\0&4&1\\0&6&7\end{array}\right] [/tex][tex]+7* \left[\begin{array}{ccc}-5&4&3\\7&0&2\\0&6&7\end{array}\right] -1* \left[\begin{array}{ccc}-5&4&3\\7&0&2\\0&4&1\end{array}\right] =7* \left[\begin{array}{cc}4&1\\6&7\end{array}\right][/tex][tex]+5*\left[\begin{array}{cc}4&1\\6&7\end{array}\right] -35*\left[\begin{array}{cc}0&2\\6&7\end{array}\right] -49*\left[\begin{array}{cc}4&3\\6&7\end{array}\right] +5*\left[\begin{array}{cc}0&2\\4&1\end{array}\right][/tex][tex] +7*\left[\begin{array}{cc}4&3\\4&1\end{array}\right]=7*22+5*22+35*12-49*10-5*8-7*8=22*(7+5)+35*12-490-40-56=12*(22+35)-586=12*57-586 =684-586=98[/tex]