найдите средние арифметическое чисел : 1 1/3 ,2 5/6 , 3 3/4

[tex] (\frac{1}{3} + 2 \frac{5}{6} + 3 \frac{3}{4}) : 3 = ( \frac{1}{3}+ \frac{17}{6}+ \frac{15}{4} ):3 = ( \frac{4+34+45}{12} ):3 = \frac{83}{12} : 3 = [/tex]
[tex]= \frac{83}{12} * \frac{1}{3} = \frac{83}{36} = 2 \frac{11}{36} [/tex]