решите уровнение 2n-1/n+4+8-6n-2n²/n²+8n+16

[tex]\displaystyle \frac{2n-1}{n+4}+ \frac{8-6n-2n^2}{n^2+8n+16} = \frac{2n-1}{n+4}+ \frac{8-6n-2n^2}{(n+4)^2} =\\ \\ \\ = \frac{2n^2-n+8n-4+8-6n-2n^2}{(n+4)^2} = \frac{n+4}{(n+4)^2} = \frac{1}{n+4} [/tex]