решите уравнение sinx-√2/2=0

[tex]\displaystyle\sin x- \frac{ \sqrt{2} }{2}=0 [/tex]

[tex]\displaystyle\sin x= \frac{ \sqrt{2} }{2} [/tex]

[tex]\displaystyle x=(-1)^n\arcsin \frac{ \sqrt{2} }{2} +\pi n,n\in \mathbb Z[/tex]

[tex]\displaystyle x=(-1)^n \frac{\pi}{4}+\pi n , n\in\mathbb Z [/tex]