Lim sin(2x-6)/(x-3) при x->3, методом Лопиталя нельзя...

 

[tex]lim_{x->3} \frac{sin(2x-6)}{x-3}=\\\\|x-3=t; t->0|=\\\\lim_{x->0} \frac{sin (2t)}{t}=\\\\2*lim_{t_>0} \frac{sin(2t)}{2t}=2*1=2[/tex]